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gayaneshka [121]
3 years ago
9

How do I work this out

Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0
If the track is 10km long, and X travels at 40 km/h, it will take 1 hour to do 4 laps. this means that car X will do one lap in 15 minutes. Y travels at 30 km/h, which means it will do 3 laps in 1 hour, meaning that car X will do 1 lap in 20 minutes.

X- 15, 30, 45, 60
Y-20, 40, 60


Therefore, after an hour, they will pass again.
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daren has 10 sweets .hellen has 30 sweets.faith has 4 fewer sweets than the average number of sweets daren,hellenand faith have.
Sunny_sXe [5.5K]

Answer:

16

Step-by-step explanation:

Average = the sum of all numbers divided by the amount of items in the set, so:

10+30=40

40/2=20

20-4=16

Hopefully this helps :) Good luck!

8 0
3 years ago
Simplify the expression -5(x+2) using the distributive property
sashaice [31]
Answer: -5x+-10 using the distributive property
4 0
3 years ago
Read 2 more answers
Find the answer, please!!​
noname [10]
X=7 is the answer and you just plug that in! Both answers should be 54°
4 0
3 years ago
Convert 13ltr into volume​
Norma-Jean [14]

Answer:

3.43424 (US liquid gallon)

Step-by-step explanation:

6 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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