Answer:
The circumference and area of a circle with a 17 ft diameter are:
C = 53.4 ft
A = 227 ft2
1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
<span>
A=(b1+b2/2)h
</span><span>
A is the area of the trapezoid.
</span><span> b1 is the larger base of the trapezoid (b1=16-4=12 ft).
</span><span> b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
</span><span> h is the height of the trapezoid (h=12-4=8 ft)
</span><span>
2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
</span><span>
A=(b1+b2/2)h
</span><span> A=(12 ft+6 ft/2)(8 ft)
</span><span> A=9 ftx8ft
</span><span> A=72 ft²
</span><span>
3. </span><span>The length of fencing is:</span> a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft
Yeah yeah I’m gonna is that the day I get home and I’m out with you I wanna is
Answer:
70.1 ft
Step-by-step explanation:
The cosine relation gives the ratio of the adjacent side to the hypotenuse for an acute angle in a right triangle:
Cos = Adjacent/Hypotenuse
cos(37°) = SQ/QR
Rearranging gives ...
QR = SQ/cos(37°) = (56 ft)/0.798636 = 70.1 ft
The length of QR is about 70.1 ft.
Answer:
56.42
Step-by-step explanation:
42 hundredths = 42/100 = 0.42
Therefore, 56 and 42 hundredths = 56 + 0.42 = 56.42
