Considering that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, it is found that it is significant at the 5% level, but not at the 1% level.
<h3>When a measure is significant?</h3>
- If p-value > significance level, the measure is not significant.
- If p-value < significance level, the measure is significant.
Using a z-distribution calculator, it is found that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, hence, this is significant at the 5% level, but not at the 1% level.
More can be learned about p-values at brainly.com/question/16313918
now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to
undefined.
now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.
![\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\ -------------------------------\\\\ \cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}](https://tex.z-dn.net/?f=%5Cbf%202-x%5E%7B12%7D%3D0%5Cimplies%202%3Dx%5E%7B12%7D%5Cimplies%20%5Cpm%5Csqrt%5B12%5D%7B2%7D%3Dx%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bx%5E2-9%7D%7B2-x%5E%7B12%7D%7D%5Cqquad%20%5Cboxed%7Bx%3D%5Cpm%20%5Csqrt%5B12%5D%7B2%7D%7D%5Cqquad%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%28%5Cpm%5Csqrt%5B12%5D%7B2%7D%29%5E%7B12%7D%7D%5Cimplies%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%5Cboxed%7B2%7D%7D%5Cimplies%20%5Cstackrel%7Bund%20efined%7D%7B%5Ccfrac%7Bx%5E2-9%7D%7B0%7D%7D)
so, the domain is all real numbers EXCEPT that one.
These are so easy, you won't believe it !
A negative exponent only means
"Put all of this in the denominator, and make the exponent positive."
So (any number)^negative power =
1 / (the same number)^(the same power but not negative) .
The first few problems on that sheet:
1). 5^-3 = 1 / 5^3
2). 6^-10 = 1 / 6^10
3). (-2)^-5 = 1 / (-2)^5
Got it ? You can do the rest of them now in about 2 minutes.
Answer: Maybe 5.7
Step-by-step explanation: To solve this we are going to need to understand the pythagorean theorem. we can use it as a way to find this certain side. if we put these numbers in the theorem, we get a^2+49=81 (7^2=49 and 9^2=81), we can subtract 49 on both sides and get 32. We would also need to take out the power of 2 on the side of the a^2, so you would do the square root of a^2, which would just become a and the square root of 32, which if you crunch the numbers on a calculator. You would get 5.656..... then you round it to the nearest tenth and get 5.7.
<span>Subtract 13.09 from 21.59 giving you 8.5. Since the amount of space on both the left and right margin have to be equal you would divide by 2 to get 4.25 on the left margin as well as the right.</span>
