Answer: $85,000
Step-by-step explanation:
Given : In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviation of $12,000.
Female earnings have a mean of $45,000 per year and a standard deviation of $18,000.
If C denote the combined earnings for a randomly selected couple.
Then, the mean of C will be :-
Hence, the mean of C = $85,000
Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:
![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)
Answer:
I'm not sure, but I think they spend 2$ for each
Step-by-step explanation:
The total items they buyed was 45. The total amount of money they spend was 95. 95 divided by 45 is 2.111111111111111111111 . So if you find 2 as one of your options, that's probably it.
x = 0, x = 
, x = - 
since we have a product of factors equal to zero, equate each factor to zero and solve for x
x² = 0 ⇒ x = 0 ( multiplicity 2 )
5x - 7 = 0 ⇒ x =
3x + 2 = 0 ⇒ x = -
C = 5/9(F - 32)...multiply both sides by 9/5, eliminating the 5/9 on the right
9/5C = F - 32...add 32 to both sides
9/5C + 32 = F <===
