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Nostrana [21]
2 years ago
5

sub to my y o t u b e. my. y o u t u b e. is stiko9 the vidoe tha says oh no primo or small skate clips or slomo kickflip is my

video just click on the video and sub thanks help me hit 20 subs.
Mathematics
2 answers:
julia-pushkina [17]2 years ago
5 0

Answer:

i said im from brainly on slo mo kickflip

Step-by-step explanation:

ArbitrLikvidat [17]2 years ago
4 0

Answer:

yay free points thanks

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What is an equation of the line that passes through the points (4, -1) and
Verizon [17]

Answer:

y= x/2-3

Step-by-step explanation:

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3 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
3 years ago
Solve the following equation. Then place the correct number in the box provided. 3 x = 12
Scorpion4ik [409]

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I believe 4 but I'm not that good at math but 4

3 0
3 years ago
Mar in was a bat and hit 7 out 8 balls. How can you find his batting precentage
777dan777 [17]
Divide 7 by 8 then multiply what you get by 100.
7 0
3 years ago
Read 2 more answers
Helppppppppppppppppp​
lions [1.4K]

Answer:

<h2>9) Multiplication</h2><h2>10) </h2><h2>\frac{3}{4}</h2><h2>11) </h2>

\frac{4}{5}

<h2>12) 0.36</h2>

<h2>13) </h2>

\frac{12}{25}

<h2>14)</h2>

\frac{1}{9}

<h2>15) 5.9</h2>

Step-by-step explanation:

<h2>This might be helpful and believe me dude, these questions are the most important questions for your exams.</h2><h2 /><h2>Keep Studying ☺️❤️</h2>
3 0
3 years ago
Read 2 more answers
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