Answer:
£36
Step-by-step explanation:
From the question, we are told that School allots £3000 to spend on a trip to the theatre. With regular cost of tickets of £40 each with offer for 1/5 off
Then the cost of each ticket with 1/5 off= (4/5×40)= £32
From the question, A train ticket for the day will cost £20 each.
Then total cost for each of it = £32+£20
=£52
To determine how much money that the school will have left over, If 3 teachers and the maximum number of students attend, can be expressed below by first calculating the number of students.
Let us denote the number of students as "x"
52(x+3)= < 3000
52x + 156 =< 3000
52x =< 3000 - 156
52x =< 2844
X =< 2844/52
s =< 54.69,
The max. Number of students is 54
Total number of people= Number of students + the 3 teachers
= 54+3= 57
Total cost for 57 people= (£52 × 57 people)= £2964
The amount of money the school will have as left over = (£3000 - £2964)
= £36
Domain means the values that can be used as a function's input. Since all real values of x will yield a real value of f(x), the domain is (-infinity, infinity).
Answer:
32768x^5
Step-by-step explanation:
Answer:
<h3>The 12th term is 1771470</h3>
Step-by-step explanation:
Since the above sequence is a geometric sequence
An nth term of a geometric sequence is given by
where a is the first term
r is the common ratio
n is the number of terms
From the question
a = 10
To find the common ratio divide the previous term by the next term
That's
r = 30/10 = 3 or 90/30 = 3 or 270/90 = 3
Since we are finding the 12th term
n = 12
So the 12th term is
<h3>A(12) = 1771470</h3>
Hope this helps you
Answer:
Check the solution below
Step-by-step explanation:
2) Given the equation
x +y =5... 1 and
x-y =3 ... 2
Add both equations
x+x = 5+3
2x = 8
x = 8/2
x = 4
Substitute x = 4 into 1:
From 1: x+y = 5
4+y= 5
y = 5-4
y = 1
3) Given
x+3y =15 ... 1
2x+7y=19 .... 2
From 2: x = 15-3y
Substitute into 2
2(15-3y)+7y = 19
30-6y+7y = 19
30+y = 19
y = 19-30
y = -11
Substitute y=-11 into x = 15-3y
x =15-3(-11)
x = 15+33
x = 48
The solution set is (48, -11)
4) given
x/2 +y/3 =0 and x+2y=1
From 1
(3x+2y)/6 = 0
3x+2y = 0.. 3
x+2y= 1... 4
From 4: x = 1-2y
Substutute
3(1-2y) +2y = 0
3-6y+2y = 0
3 -4y = 0
4y = 3
y = 3/4
Since x = 1-2y
x = 1-2(3/4)
x = 1-3/2
x= -1/2
The solution set is (-1/2, 3/4)
5) Given
5.x=1/2 and y =x +1 then solution is
We already know the vkue of x
Get y
y= x+1
y = 1/2 + 1
y = 3/2
Hence the solution set is (1/2, 3/2)
6) Given
3x +y =5 and x -3y =5
From 3; x = 5+3y
Substitute into 1;
3(5+3y)+y = 5
15+9y+y = 5
10y = 5-15
10y =-10
y = -1
Get x;
x = 5+3y
x = 5+3(-1)
x = 5-3
x = 2
Hence two solution set is (2,-1)
