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2 years ago

(Im giving brainliest and extra points on this one :D)

Mathematics

2 answers:

Studentka2010 [4]2 years ago

5 0

Answer:

Step-by-step explanation:

Convert to improper fraction and multiply them, then convert back to mixed fraction :)

garik1379 [7]2 years ago

4 0

Answer:

C . The answer can be simplified but its not on here for some reason.

Step-by-step explanation:

6 2/6 x 1 1/2

(6 x 6) + 2 = 38/6

(1 x 2) + 1 = 3/2

38/6 x 3/2 = 114/12

114 ÷ 12 = 9 6/12.

9 6/12 = 9 3/6 = 9 1/2.

Again it can be simplified buts it not on here for some reason.

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A is two years older than b who is twice as old as c. If the total of the ages of a, b and c be 27, then how old is b?.

RoseWind [281]

A is 12 years
b is 10 years
c is 5 years

8 0

2 years ago

Log base 2 (1/4) ...?

liubo4ka [24]

Log ( base 2 ) ( 1 / 4 ) =
= log ( base 2 ) ( 2 ^(-2 ) ) =
= - 2 log ( base 2 ) 2 = ( because : log x^n = n log x )
= ( - 2 ) * 1 = ( because: log (base x) x = 1 )
= - 2

5 0

3 years ago

Michael and Kathryn bowl together and their combined total score for one game was 425points. Michael’s score was 70 less than tw

In-s [12.5K]

Hey there!

Let us take Michael's score as ' x '

Let us take Kathryn's score as ' y '

Michael - 70 less than twice Kathryn's

x = 2y - 70

y = y

Add them, we get , 425

2y - 70 + y = 425

3y - 70 = 425

3y = 495

y = 495/3

y = 165

Kathryn's score = 165

Michael - 2 ( 165 ) - 70

= 260

Hope it helps!

7 0

3 years ago

F(x, y, z) = yzexzi + exzj + xyexzk,

Ghella [55]

$\nabla f(x,y,z)=\mathbf F(x,y,z)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\dfrac{yz}ze^{xz}+g(y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f}{\partial y}=e^{xz}=e^{xz}+\dfrac{\partial g}{\partial y}$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\mathrm dh}{\mathrm dz}$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$f(x,y,z)=ye^{xz}+C$

$\mathbf r(t)=(t^2+5)\,\mathbf i+(t^2-1)\,\mathbf j+(t^2-5)\,\mathbf k$
$\implies\mathbf r(0)=5\,\mathbf i-\mathbf j-5\,\mathbf k$
$\implies\mathbf r(5)=30\,\mathbf i+24\,\mathbf j+20\,\mathbf k$

By the gradient theorem, we have for any path $\mathcal C$ originating at the point (5, -1, -5) and terminating at the point (30, 24, 20),

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=f(\mathbf r(5))-f(\mathbf r(0))=f(30,24,20)-f(5,-1,-5)$
$\implies\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=24e^{600}+e^{-25}$

4 0

3 years ago

WHATS 45X3 WITH THE SECOND POWER? WILL MAKE BRAINLIEST+10 POINTS

lilavasa [31]

45x3 is 135. And then when you square 135 you would get 18,225

8 0

3 years ago