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dybincka [34]
3 years ago
13

Sabe-se que no inventário periódico, o registro contábil do estoque de mercadorias ocorrerá apenas no final de um determinado pe

ríodo com a contagem física das quantidades existentes. Considere as seguintes informações: CMV = 500,00; Estoque Inicial = 700,00 e Compras = 800,00. Aplicando o conceito do inventário periódico e aplicando a fórmula para apuração do CMV, apure o valor do estoque final. Alternativas Alternativa 1: Estoque final de 2.000,00. Alternativa 2: Estoque final de 1.500,00. Alternativa 3: Estoque final de 1.300,00. Alternativa 4: Estoque final de 1.200,00. Alternativa 5: Estoque final de 1.000,00.
Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

Answer:

It is known that in the periodic inventory, the accounting record of the stock of goods will occur only at the end of a certain period with the physical count of the existing quantities. Consider the following CVM information = 500.00; Initial Inventory = 700.00 and Purchases = 800.00. Applying the concept of periodic inventory and applying the formula for calculating the CMV, determine the value of the final stock.

ALTERNATIVES

Final stock of 2,000.00.

Final stock of 1,500.00.

Final stock of 1,300.00.

Final stock of 1,200.00.

Final stock of 1,000.00.

Final Stock (EF)  = 1,000.00

Step-by-step explanation:

Alternative E -  Final stock of 1,000.00.

Given That,

CMV = 500,00

Initial Stock (EI) = 700.00

Purchases (C) =  800.00

Final Stock (EF)  = ?

Formula

CMV = Initial Stock (EI) + Purchases (C) - Final Stock (EF)

CMV = EI + C - EF

500 = 700 + 800 - EF

500.00 = 700.00 + 800.00 -X

500 = 1500- EF

500.00 = 1,500.00-X

EF = 1500-500

X = 1,000.00

EF = 1,000.00

Therefore, the final stock is 1,000

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If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to
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See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

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The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

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Find area ABC and CPQ then compare the areas.

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AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units

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1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

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PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units

Length of side QC will be;

QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c)  where;

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Finding the perimeter of triangle CPQ will be;

P=sum of all sides

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s=10.6/2 = 5.3

Area of the triangle CPQ will be;

A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98

A=3.0 (1 decimal place)

Compare the areas;

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Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

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