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leva [86]
2 years ago
7

Your teacher recently found an old Nintendo in a thrift store. Use the formula to predict the value of the Nintendo in 2020. (Re

member, x is the years after 1986, and y is the
value, in $.) Do you think this is a realistic prediction of the value of that Nintendo?
Formula- f(x) = 3x^2 - 40x + 180
Mathematics
1 answer:
9966 [12]2 years ago
4 0

The value of the Nintendo after 35 years is $2455

Since the formula f(x) = 3x² - 40x + 180 predicts the value of the Nintendo x years after 1986.

Since we require the value in 2021, x years after 1986 is 2021 - 1986 = 35 years.

Substituting x = 35 into the equation, we have

f(x) = 3x² - 40x + 180

f(x) = 3(35)² - 40(35) + 180

f(x) = 3(1225) - 40(35) + 180

f(x) = 3675 - 1400 + 180

f(x) = 2275 + 180

f(x) = 2455

So, the value of the Nintendo after 35 years is $2455

Do you think this is a realistic prediction of the value of that Nintendo?

This is not a realistic prediction for the value of the Nintendo, because, it is too high.

Learn more about quadratic equations here:

brainly.com/question/13704125

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alexandr1967 [171]

Answer:

Non-repeating decimal

Step-by-step explanation:

As a example, 32.93729, would be a never ending number. Which means it's not a rational number, it is a irrational number.

6 0
3 years ago
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Which is the closest to the area that is painted blue? A 308 units B. 116 units C. 463 units? D 124 units
Charra [1.4K]

Step-by-step explanation:

first of all, all answer options are basically wrong, because an area is always measured in units² (and not just in units).

the blue colored area is the area of the whole square minus the area of the circle.

the side length of the square is 2 times the radius of the circle (the diameter) : 2×12 = 24 units.

so, the area of the square is

24² = 576 units²

the are of the circle is

pi×r² = pi×12² = 144pi units²

so, the blue area is

576 - 144pi = 123.6106579... ≈ 124 units²

therefore, D is the right answer.

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2 years ago
Solve the literal equation for x. <br><br> w=5+3(x−1)
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Isolate the variable by dividing each side by factors that don't contain the variable.

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4 0
3 years ago
Please help! URGENT! will award 30 points &amp; brainliest!
Alekssandra [29.7K]

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4 0
3 years ago
Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos
Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$ P_{1} = (- 1, 4) $

$ P_{2} = (6, 2) $    and

$ P_{3} = (4, - 5) $

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $ (x_1, y_1) $ and $ (x_2, y_2) $ is:

                                 $ \sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+}   \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}} $

Length between $ P_1 $ and $ P_{2} $ , (Side 1) :

$ (x_1, y_1) = (- 1, 4) $     and

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2 $

$ = \sqrt{7^2 + 2^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53}} $

Length of Side 1 = $  \sqrt{\textbf{53}} $ units.

Distance between $ P_1 $ and P_2 , (Side 2):

$ (x_1, y_1) = (-1, 4) $

$ (x_2, y_2) = (4, - 5) $

Distance = $ \sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2 $

$ = \sqrt{ 25 + 81 } $

$ = \sqrt{\textbf{106}} $

Length of Side 2 = $ \sqrt{\textbf{106}} $ units.

Distance between $ P_2 $ and $ P_3 $ , Side 3 :

$ (x_1, y_1) = (4, 5) $

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53} $

Length of Side 3  = $ \sqrt{\textbf{53}} $ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$ \bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2 $

i.e, 53 + 53  = 106

Hence, the triangle is a right - angled triangle as well.

7 0
3 years ago
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