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leva [86]
2 years ago
7

Your teacher recently found an old Nintendo in a thrift store. Use the formula to predict the value of the Nintendo in 2020. (Re

member, x is the years after 1986, and y is the
value, in $.) Do you think this is a realistic prediction of the value of that Nintendo?
Formula- f(x) = 3x^2 - 40x + 180
Mathematics
1 answer:
9966 [12]2 years ago
4 0

The value of the Nintendo after 35 years is $2455

Since the formula f(x) = 3x² - 40x + 180 predicts the value of the Nintendo x years after 1986.

Since we require the value in 2021, x years after 1986 is 2021 - 1986 = 35 years.

Substituting x = 35 into the equation, we have

f(x) = 3x² - 40x + 180

f(x) = 3(35)² - 40(35) + 180

f(x) = 3(1225) - 40(35) + 180

f(x) = 3675 - 1400 + 180

f(x) = 2275 + 180

f(x) = 2455

So, the value of the Nintendo after 35 years is $2455

Do you think this is a realistic prediction of the value of that Nintendo?

This is not a realistic prediction for the value of the Nintendo, because, it is too high.

Learn more about quadratic equations here:

brainly.com/question/13704125

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1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)

400=81+169-234(cosA)   150=-234(cosA)

cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

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3 years ago
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50 points find the area
mixer [17]

Answer:

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Step-by-step explanation:

Split the area into two sections by extending 6 in segment.

We get a rectangle of 5 in x 10 in and a trapezoid.

<u>Rectangle:</u>

  • A = wl
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<u>Trapezoid:</u>

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<u>Total area:</u>

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2 years ago
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Find the area of the regular polygon below and round your answer to the nearest tenth.
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3 years ago
Simplify.<br> (w^2 + 3w)-(w^2+5w-4<br><br> 8w-4<br> 2w^2 +8w-4<br> -2w+4<br> -2w
chubhunter [2.5K]

Answer:

-2w + 4

Step-by-step explanation:

Remove parenthesis because they make life semi-confusing but remember to distribute the negative: w^2 + 3w -w^2 - 5w + 4

Combine like terms: w^2 - w^2 cancel out ; 3w - 5w = -2w ; 4

-2w + 4

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3 years ago
What is the value of x in the equation -2/9x=2/5
densk [106]

Answer:

x = (-9)/5

Step-by-step explanation:

Solve for x:

(-2 x)/9 = 2/5

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (-2 x)/9 = 2/5 by -9/2:

(-9 (-2) x)/(2×9) = (-9)/2×2/5

Hint: | Express (-9)/2×(-2)/9 as a single fraction.

(-9)/2×(-2)/9 = (-9 (-2))/(2×9):

(-9 (-2))/(2×9) x = (-9)/2×2/5

Hint: | Express (-9)/2×2/5 as a single fraction.

(-9)/2×2/5 = (-9×2)/(2×5):

(-9 (-2) x)/(2×9) = (-9×2)/(2×5)

Hint: | In (-9 (-2) x)/(2×9), divide -9 in the numerator by 9 in the denominator.

(-9)/9 = (9 (-1))/9 = -1:

(-2-1 x)/2 = (-9×2)/(2×5)

Hint: | In (-(-2) x)/2, divide -2 in the numerator by 2 in the denominator.

(-2)/2 = (2 (-1))/2 = -1:

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Hint: | Multiply all instances of -1 in -(-x).

(-1)^2 = 1:

x = (-9×2)/(2×5)

Hint: | Cancel common terms in the numerator and denominator of (-9×2)/(2×5).

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Answer: x = (-9)/5

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