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3 years ago

Find the circumference of the following circle. Use 3.14 for π. Round to the nearest hundredth

Mathematics

2 answers:

Digiron [165]3 years ago

8 0

Answer:

56.55

Step-by-step explanation:

C=2πr=2·π·9≈56.54867cm

LuckyWell [14K]3 years ago

5 0

Formula for the circumference of a circle:

C = 2πr (C = circumference π(pi) = 3.14..... r = radius)

You know:

r = 9 cm

π = 3.14 So substitute/plug it into the equation

C = 2πr

C = 2(3.14)(9)

C = 56.52 cm

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Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago

I need help please.

GuDViN [60]

Answer:

The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

Step-by-step explanation:

The given expression is:

2q²-5pq-2q+5p

Make a pair of first two terms and last two terms:

(2q²-5pq) - (2q-5p)

Now factor out the common factor from each group.

Note that there is no common factor in second group. So we will take 1 as a common factor.

q(2q-5p) -1(2q-5p)

Now factor the polynomial by factoring out the G.C.F, 2q-5p

(2q-5p) (q-1)

Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

4 0

3 years ago

Please help i dont get this at all

Tom [10]

Answer:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

Step-by-step explanation:

1) Flip the second fraction and change the operation to multiplication:

$\frac{5x^{2}y^{3} }{2a^{5}b^{4} } * \frac{8a^{7}b^{3} }{41x^{5}y }$

2) Cross cancel factors:

$\frac{5y^{2} }{2b } * \frac{8a^{2} }{41x^{3} }$

3) Multiply:

$\frac{40y^{2} a^{2} }{82bx^{3} }$

4) Simplify:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

4 0

3 years ago

Read 2 more answers

Jessica and Emily went shopping at a local boutique. Jessica purchased 4 bracelets and a new.pair of earrings for $9.50. Emily p

Radda [10]

What’s the complete question

5 0

3 years ago

Can you help my brother so I can help him! How can you subtract 5 2/12 - 1 9/12

Lana71 [14]

Answer: $\frac{41}{12}$ , or as a mixed number, 3 $\frac{5}{12}$

Step-by-step explanation:

It helps to simplify them.

6 0

3 years ago