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3 years ago

Find the circumference of the following circle. Use 3.14 for π. Round to the nearest hundredth

Mathematics

2 answers:

Digiron [165]3 years ago

8 0

Answer:

56.55

Step-by-step explanation:

C=2πr=2·π·9≈56.54867cm

LuckyWell [14K]3 years ago

5 0

Formula for the circumference of a circle:

C = 2πr (C = circumference π(pi) = 3.14..... r = radius)

You know:

r = 9 cm

π = 3.14 So substitute/plug it into the equation

C = 2πr

C = 2(3.14)(9)

C = 56.52 cm

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Tess rolls 2 fair dice. <br> What is the probability of obtaining two 4's?

harina [27]

Answer:

1/36

Step-by-step explanation:

Since Tess rolled 2 different dices, there are 36 different possibilities. Rolling two 4's is 1 of them.

Therefore, the probability of Tess rolling 2 fair dice is 1/36

Hope this helped have a great rest of your day!

4 0

3 years ago

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4/6 simplfy it can someone help

Gemiola [76]

4/6=2/3 (divide both numerator and denominator by 2 (gcd)).

Hope this helps.

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3 years ago

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Suppose θ is an angle in the standard position whose terminal side is in Quadrant IV and cot θ= -6/7 . Find the exact values of

Llana [10]

Answer:

Part 1) $csc(\theta)=-\frac{\sqrt{85}}{7}$

Part 2) $sin(\theta)=-\frac{7}{\sqrt{85}}$ or $sin(\theta)=-\frac{7\sqrt{85}}{85}$

Part 3) $tan(\theta)=-\frac{7}{6}$

Part 4) $cos(\theta)=\frac{6}{\sqrt{85}}$ or $cos(\theta)=\frac{6\sqrt{85}}{85}$

Part 5) $sec(\theta)=\frac{\sqrt{85}}{6}$

Step-by-step explanation:

we know that

The angle theta lie on the IV Quadrant

sin(θ) is negative

cos(θ) is positive

tan(θ) is negative

sec(θ) is positive

csc(θ) is negative

step 1

Find the value of csc(θ)

we know that

$1+cot^{2}(\theta)=csc^{2}(\theta)$

we have

$cot(\theta)=-\frac{6}{7}$

substitute

$1+(-\frac{6}{7})^{2}=csc^{2}(\theta)$

$1+\frac{36}{49}=csc^{2}(\theta)$

$\frac{85}{49}=csc^{2}(\theta)$ rewrite

$csc(\theta)=-\frac{\sqrt{85}}{7}$ ----> remember that is negative

step 2

Find the value of sin(θ)

we know that

$csc(\theta)=\frac{1}{sin(\theta)}$

we have

$csc(\theta)=-\frac{\sqrt{85}}{7}$

therefore

$sin(\theta)=-\frac{7}{\sqrt{85}}$

$sin(\theta)=-\frac{7\sqrt{85}}{85}$

step 3

Find the value of tan(θ)

we know that

$tan(\theta)=\frac{1}{cot(\theta)}$

we have

$cot(\theta)=-\frac{6}{7}$

therefore

$tan(\theta)=-\frac{7}{6}$

step 4

Find the value of cos(θ)

we know that

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$sin(\theta)=-\frac{7}{\sqrt{85}}$

substitute

$(-\frac{7}{\sqrt{85}})^{2}+cos^{2}(\theta)=1$

$\frac{49}{85}+cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{49}{85}$

$cos^{2}(\theta)=\frac{36}{85}$

$cos(\theta)=\frac{6}{\sqrt{85}}$ ------> the cosine is positive

$cos(\theta)=\frac{6\sqrt{85}}{85}$

step 5

Find the value of sec(θ)

we know that

$sec(\theta)=\frac{1}{cos(\theta)}$

we have

$cos(\theta)=\frac{6}{\sqrt{85}}$

therefore

$sec(\theta)=\frac{\sqrt{85}}{6}$ ----> is positive

8 0

4 years ago

A rectangular prism has a height of 15 centimeters and a width of 6 centimeters. The surface area of the prism is 684 square cen

Gala2k [10]

Answer:

Step-by-step explanation:

Let the length be L

Formula

SA = 2Lw + 2Lh + 2wh

Givens

h = 15 cm

w = 6 cm

L = ?

SA = 684 cm^2

Solution

Substitue what you know into the given formula

2*6*L + 2*15*L + 2 * 6 * 15 = 684 Combine

12*L + 30*L + 180 = 684 Combine again

42L + 180 = 684 Subtract 180 from both sides.

42L +180 -180 = 684 - 180

42L = 504 Divide by 42

Answer: L = 12

7 0

2 years ago

Write an equation about money. You started with $9. You spent some of it. Now you have $5.

KIM [24]

Answer:

9-4=5

Step-by-step explanation:

6 0

4 years ago

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