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zhuklara [117]
3 years ago
15

Help? >K12<

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
The correct answer is a) Amy's solutions are correct.

Since she wanted the intersection point of the equations, she had to set them equal.  Once she did she had

x²+3x-5=4x+1

Gathering the variables on one side of the equation, she subtracted 4x from each side:
x²+3x-5-4x=4x+1-4x
x²-x-5=1

Quadratics should be equal to 0 when we solve them, so she subtracted 1 from each side:
x²-x-5-1=1-1
x²-x-6=0

She then factored her expression; factors of -6 that sum to -1 are -3 and 2:
(x-3)(x+2)=0

Using the zero product property we know that either x-3=0 or x+2=0; therefore x=3 or x=-2.
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\\ \sf\longmapsto LB=Area

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