3 years ago

Can you help me on a math problem?

Mathematics

1 answer:

Fudgin [204]3 years ago

8 0

Answer:

18...................

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For 8x2 - 2x-3=0, a = 8, b=_

lianna [129]

Answer:

A = 8 B = -2 C = -3

Step-by-step explanation:

The standard form for a quadratic equations is

Ax^2 + Bx +C =0

8x2 - 2x-3=0

A = 8 B = -2 C = -3

6 0

3 years ago

How to simplify 7-|-23|+|-7|

Scilla [17]

Ok The answer is : -7

Simply -7 to 7:

7-21+7

Simplify and the answer is -7

hope this helps.

5 0

3 years ago

Read 2 more answers

Pls help I dont understand. Find the inverse of this function.

lisov135 [29]

In the inverse we replace the place of x by y .

$g(x) = \sqrt[3]{x} - 3 \\ \\ x = \sqrt[3]{y} - 3 \\ \sqrt[3]{y} = x + 3 \\ y = {(x + 3)}^{3} \\ y = {(x + 3)}^{2} (x + 3) \\ y = ({x}^{2} + 6x + 9)(x + 3) \\ \\ y = {x}^{3} + 6 {x}^{2} + 9x + 3 {x}^{2} + 18x + 27 \\ \\ y = {x}^{3} + 9 {x}^{2} + 27x + 27 \\ \\ \\ g(x)^{ - 1} = {x}^{3} + 9 {x}^{2} + 27x + 27$

I hope I helped you^_^

8 0

3 years ago

Let f(x) = x^2 - 11x - 60.<br> Solve for f(x) using factoring.

Alona [7]

F(x) = X^2 - 11x - 60
Two terms that multiply to -60 and add to -11 so...
F(x) = (X - 15) (x + 4)
Your x-intercepts would be 15 and -4.

4 0

3 years ago

The length of a rectangle is 3 cm more than twice the width. The area of the rectangle is 65 square centimeters. Find the dimens

polet [3.4K]

Answer:

5 cm and 13 cm

Step-by-step explanation:

Let b be the width of the rectangle.

Length = 3+2b

The area of the rectangle is 65 cm²

We need to find the dimensions of the rectangle. The area of a rectangle is given by :

A = lb

$65=(3+2b)b\\\\65=3b+2b^2\\\\3b+2b^2-65=0\\\\b=5\ cm,-6.5\ cm$

Neglecting the negative value, the width of the rectangle is 5 cm.

Length = 3+2b

=3+2(5)

=3+10

=13 cm

Hence, the dimensions of the rectangle are 5 cm and 13 cm.

6 0

3 years ago