Move the decimal right 3 times
<span>1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x
2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1).
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69
3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line.
4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2
5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2
6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4) / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7
7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11
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Answer:
y=x+1/2z+-1/2
Step-by-step explanation:
Let's solve for y.
2x−2y+z=1
Step 1: Add -2x to both sides.
2x−2y+z+−2x=1+−2x
−2y+z=−2x+1
Step 2: Add -z to both sides.
−2y+z+−z=−2x+1+−z
−2y=−2x−z+1
Step 3: Divide both sides by -2.
-2y/-2 = -2-z+1/-2
y=x +1/2z+-1/2
Hey there! :)
Your answer is: Between 11 and 12
11² = 11 × 11 = 121
12² = 12 × 12 = 144
129 is between 121 and 144
Hope this helps :)
