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3 years ago

Creating a bar graph can display data so that it is easily understood. Today you will have an opportunity to create a bar

Mathematics

1 answer:

ryzh [129]3 years ago

8 0

Answer:

that is so much work um. i believe you have to graph first and look at the given problems

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−14a−(−48a)<br> mind helping

MrRa [10]

Answer:

34a

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The probability that Fred's bus is late on any day is 0.09.

miv72 [106K]

Answer:

The bus would be 36 times late in 400 times of when Fred takes the bus

Step-by-step explanation:

Given that the probability of being the bus late is 0.09.

In order to find the number of times the bus will be late will be calculated by multiplying the total number of observations by probability.

It is also given that the total number of days he waits for bus is 400 times.

So,

The bus will be:

$= 0.09*400\\=36$

Hence,

The bus would be 36 times late in 400 times of when Fred takes the bus

6 0

3 years ago

Find Integrating Fector: <br> ylogy dx + ( x-logy )dy=0

12345 [234]

Rewrite the ODE as

$y\log y\,\mathrm dx+(x-\log y)\,\mathrm dy=0\iff y\log y\dfrac{\mathrm dx}{\mathrm dy}+x=\log y$
$\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1{y\log y}x=\dfrac1y$

so that it is now linear in $x$ . An integrating factor would

$\mu(y)=\exp\left(\displaystyle\int\frac{\mathrm dy}{y\log y}\right)=e^{\log(\log y)}=\log y$

Multiply both sides by $\mu(y)$ to get

$\log y\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1yx=\dfrac{\log y}y$
$\dfrac{\mathrm d}{\mathrm dy}[x\log y]=\dfrac{\log y}y$
$x\log y=\displaystyle\int\frac{\log y}y\,\mathrm dy$
$x\log y=\dfrac12\log^2y+C$
$x=\dfrac12\log y+\dfrac C{\log y}$

4 0

3 years ago

2x-3y=4<br> -4x+6y=-8. <br> solve by elimination

oksano4ka [1.4K]

$2x-3y=4 \\
-4x+6y=-8 \ \ \ |\div 2 \\ \\
2x-3y=4 \\
\underline{-2x+3y=-4} \\
2x-2x-3y+3y=4-4 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}$

4 0

4 years ago

Read 2 more answers

A ball is thrown from an initial height of 4 feet with an initial upward velocity of 30 feet per second.

bonufazy [111]

Answer:

I guess that we want to find the position equation for the ball.

First, we know that any object that is in the air has acceleration equal to the gravitational acceleration (where we ignore forces like air resistance and others) so we can write the acceleration equation as:

a(t) = -32 ft/s^2

Where 32 ft/s^2 is the gravitational acceleration, and the negative sign is because this acceleration is downwards.

To get the velocity equation, we can integrate over time to get:

v(t) = (-32 ft/s^2)*t + v0

where v0 is the initial velocity.

We know that the ball is thrown upwards with a velocity of 30 ft/s, then:

v0 = 30ft/s

And the velocity equation becomes:

v(t) = (-32 ft/s^2)*t + 30 ft/s

Finally, for the position equation we need to integrate again, to get:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (30 ft/s)*t + p0

where p0 is the initial position.

We know that the ball is thrown from an initial height of 4 ft, then:

p0 = 4ft

Then the position equation (or height equation) of the ball is:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (30 ft/s)*t + 4 ft

5 0

3 years ago