Answer:
<em>The </em>calculated value t = 3.032 > 1.9904 at 5% level of significance
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given mean of the population 'μ'=75 feet
Given mean of the sample(x⁻) = 77
Given standard deviation of the sample(S) = 5.9
Given sample size 'n' =80
<u><em>Step(ii):-</em></u>
Test statistic
t = 3.032
Degrees of freedom ν=n-1 = 80-1 =79
tabulated value = 1.9904 at 5% level of significance
The calculated value t = 3.032
<u><em>Final answer:-</em></u>
<em>The </em>calculated value t = 3.032 > 1.9904 at 5% level of significance