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ValentinkaMS [17]
4 years ago
10

Raul used the steps shown below to solve the equation. In which step did Raul make a mistake?

Mathematics
2 answers:
natta225 [31]4 years ago
8 0
I believe a mistake was made on step 2.
Vedmedyk [2.9K]4 years ago
4 0

5x-3(2x+7)=2x+9

This is the equation and Raul had to solve it for x

So he started with simplifying the parenthesis first

To simplify the parenthesis -3 gets multiplied with 2x and 7 , to get rid of parenthesis

So it came out to be

5x-3(2x+7)=2x+9

STEP-1

5x-6x -21 = 2x+9 , So the STEP-1 is correct,

After this in Step -2 , he has combined the like terms on left side, the like terms are 5x and -6x , 5x-6x should combine to -x , because 5-6 = -1

So

STEP-2

-x -21 = 2x+9 , So STEP -2 is INCORRECT

So he made a mistake in STEP-2

After that subtract 2x from both sides

-3x -21 = 9

add 21 to both sides

-3x = 30

divide both sides by -3

x=-10



Hence Option B is correct , he made a mistake in STEP -2

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

<em>Given  </em>

<em>                   </em>\frac{3^{-5} X 10^{-5} X 125 }{5^{-7} X 6 ^{-5}  }<em></em>

<em>on simplification , we get</em>

<em>          =        </em>\frac{3^{-5} X (5 X 2)^{-5} X(5)^{3}  }{5^{-7} X (3 X 2) ^{-5}  }<em></em>

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<em>(ab)ⁿ = aⁿ b ⁿ      </em>

<em>   </em>

<em>           = </em>\frac{3^{-5} X (5)^{-5} X (2)^{-5} X(5)^{3}  }{5^{-7} X{(3^{-5} } )(2) ^{-5}  }<em></em>

<em>after cancellation , we get</em>

<em></em>

<em>        =    </em>\frac{ (5)^{-5} X(5)^{3}  }{5^{-7}  }<em>  </em>

<em>       =   </em>(5)^{-5} X(5)^{3} X (5)^{7}<em></em>

<em>       = 5⁻⁵⁺³⁺⁷</em>

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<u><em>final answer:-</em></u>

<em></em>\frac{3^{-5} X 10^{-5} X 125 }{5^{-7} X 6 ^{-5}  } = 3125<em></em>

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