To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
342
Explanation (18*8)+(9*10)+(18*6)
7k/3 = 21
x 3 x3
7k = 63
/7 /7
k = 9
(7(9)/3 = 21 = 63/3 = 21 = 21 = 21)
Answer:
a. y = (3/5)× x +1
Step-by-step explanation:
y= mx+c
m = (13-4)/(20-5) = 9/15 = 3/5
c= 1
so, y= mx+c becomes y= (3/5) × x +1