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vredina [299]
2 years ago
6

Find the number of terms in the geometric progression 7,21,63,..., 45927.

Mathematics
2 answers:
Doss [256]2 years ago
6 0
The rule is times 3

7 x 3 = 21
21 x 3 = 63

and so on until 45927
Degger [83]2 years ago
4 0
What lists are the easiest to count? If you were given a list like 1, 2, 3, 4, ... , 20, it would be pretty easy to determine that there were 20 terms in the sequence. We can transform most sequences to that form to make our job of counting terms a lot easier.

First, we notice that the terms all seem to be multiples of 7. We can start to simplify our list by <em>dividing</em> each term by 7:

7,21,63,\dots,45927\rightarrow1,3,9,\dots,6561

Looking at our new list, you might notice that our numbers all seem to be <em>powers of 3</em>. 1=3^0,3=3^1,9=3^2, and you can verify that 6561=3^8

We can now transform our list again, replacing each term with its corresponding power:

1,3,9,\dots,6561\rightarrow0,1,2,\dots,8

Now, we simply add 1 to each term and:

0,1,2,\dots,8\rightarrow1,2,3,\dots,9

Voila! There are 9 terms in the sequence.
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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0
3 years ago
Find all missing angles.
Monica [59]
1=51
2=34
3= 95 (i think)
4=38
6 0
2 years ago
I need help with question 18 PLS!!!!
dolphi86 [110]

Answer:

162

Step-by-step explanation:

( -a ) ( b ) ( -a + b )

-6 ( 3 ) ( -6 + -3 )

-6 ( 3 ) ( -9 )

 - 18 ( -9 )

     162

6 0
2 years ago
2.6-,2.061,2.601,2.34,2.7 order the following from least to greatest
kondaur [170]

Answer:

2.061, 2.34, 2.6, 2.601, 2.7

Step-by-step explanation:

Hello!

This is a bit hard to explain! If you want me to try, just comment.

I have arranged the sequence in ascending order below:

2.061,\:2.34,\:2.6,\:2.601,\:2.7.

Hope this helps!

4 0
2 years ago
Read 2 more answers
What is square root of 1+sinx/1+cos x.
Juli2301 [7.4K]

Answer:

the sqaure root of 1 is 1

Step-by-step explanation:

7 0
2 years ago
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