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Kaylis [27]
3 years ago
11

If a polynomial function f(x) has roots 3±√5 and -6, what must be a factor of f(x)?

Mathematics
2 answers:
Tems11 [23]3 years ago
8 0
The answer to this question is B
Anuta_ua [19.1K]3 years ago
8 0

Answer:

B. (x - (3 -√5)).

Step-by-step explanation:

That would be (x - (3 -√5)) or  (x - (3 +√5)).

The answer is   (x - (3 -√5))

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Answer:

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Step-by-step explanation:

Factor using difference of cubes and set each factor equal to 0.

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English pls coz I don’t understand
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Type the correct answer in each box. Spell all words correctly.
sladkih [1.3K]

Answer:

Reflection

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find the a26 arithmetic sequence: -15,-35,-55,-75<br> -515 <br> 460 <br> -490
Vlad [161]

Step-by-step explanation:

<h3><u>QU</u><u>ESTION</u><u>:</u><u>-</u></h3>

<u>Fin</u>d 26th term of the A.P --15,-35,-55,-75...

<h3><u>Solu</u><u>tion</u><u>:</u><u>-</u></h3>

First term=a=-15

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We know that

\boxed{\sf a_n=a+(n-1)d}

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+(26-1)(-20)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+25(-20)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+(-500)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15-500

\\ \:\:\:\:\sf {:}\dashrightarrow {\boxed{\bf a_{26}=-515}}

6 0
3 years ago
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