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aliya0001 [1]
3 years ago
7

You are looking for a certain bacteria species in a person's microbiome. You know that if the species is present, it will make u

p a very tiny proportion of the overall microbiome. What should you change about your experiment to increase your chances of finding this species if it is present?
Biology
1 answer:
bija089 [108]3 years ago
4 0

Answer:

To increase the chance of finding this species, what is suggested is to increase the number of samples evaluated in the person's microbiome. On the one hand we can increase the sample size or the number of samples of the experiment. Another possibility is to take samples from different parts of the body.

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Help please! our existing body of scientific knowledge was developed
ahrayia [7]

Answer:

The answer should be C: mostly in the 20th century

Explanation:

5 0
3 years ago
2. In the citric acid cycle, malate is oxidized to oxaloacetate by the enzyme malate dehydrogenase, which uses NAD+ as an electr
atroni [7]

Answer:

NAD+ act both as coenzyme as well as electron acceptor compound and get reduced to NADH by accepting electron.

Explanation:

NAD+ act as co enzyme of various biological catalyst such as malate dehydrogenase, isocitrate dehydrogenase etc.

             NAD+ can act as co enzyme only in its oxidized form but not in its reduced form called NADH.

         Many reaction needs NAD+ to occur such as conversion of glyceraldehyde 3 phosphate to 1,3 bisphosphoglycerate, malate to oxaloacetate.

              That"s why NAD+/NADH ratio is kept very high because if this ratio bychance get  low then it will hamper the normal redox potential of NAD+/NADH.As a result many biochemical reaction will not take place.

6 0
3 years ago
Phenylketonuria, PKU, is a single-gene recessive human
astraxan [27]

Answer:

1/2

Explanation:

Let's assume that the allele "p" is responsible for PKU in the homozygous state. According to the given information, both the parents are unaffected by the disorder but have an affected child. This means that both the parents carry at least one copy of the recessive allele responsible for the disease. Therefore, the genotype of each of the parents is Pp. A cross between Pp and Pp would produce progeny in following ratio=

Pp x Pp = 1/4 PP: 1/2/ Pp: 1/4 pp

Therefore, the probability that their next child will carry just one recessive allele is 1/2.  

3 0
3 years ago
A hypothesis determines ...
statuscvo [17]

Answer:

the correct answer would be C.

Explanation:

it would be C because a hypothesis is your guess of what the results will be. once you test the product you will figure out if your hypotheses was correct or not.

i hope this helps you out!!

-AlphaWolfie-

8 0
2 years ago
PLS HELPP MEEEE I WILL GIVVEE BRAINLIEST
Alexandra [31]

hope this helps :):):):):):):):):):)

4 0
3 years ago
Read 2 more answers
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