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Vika [28.1K]
3 years ago
9

A square has a perimeter of 48 cm 48 cm48 cm. What is the length of one side of the square?

Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer6

Step-by-step explanation:

Liula [17]3 years ago
6 0

Given that the perimeter of the square is 48 cm.

We need to determine the length of one side of the square.

<u>Length of the square:</u>

The length of one side of the square can be determined using the perimeter formula.

The formula is given by,

P=4a

Substituting P=48 in the above formula, we get;

48=4a

Dividing both sides of the equation by 4, we have;

12=a

Thus, the value of a is 12 cm.

Hence, the length of the one side of the square is 12 cm.

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What is 6P4<br> permutations and combinations
labwork [276]

Answer:

360

Step-by-step explanation:

Here we are required to find _^{6}\textrm{P}_{4}

It is a problem of Permutation and we must understand the formula for finding permutations.

The general formula for finding the permutation is given as below:

_^{m}\textrm{P}_{n}=\frac{m!}{(m-n)!}

Hence

_^{6}\textrm{P}_{4}=\frac{6!}{(6-4)!}

_^{6}\textrm{P}_{4}=\frac{6!}{2!}

Where

m!=m\times(m-1)\times\(m-2)\times\cdot\cdot\cdot\codt\cdot3\times2\times1

6!=6\times5\times4\times3\times2\times1

2!=2\times1

Hence

_^{6}\textrm{P}_{4}=\frac{6\times5\times4\times3\times2\times1}{2\times1}

_^{6}\textrm{P}_{4}=6\times5\times4\times3

_^{6}\textrm{P}_{4}=360

3 0
3 years ago
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Solve this system of equations by using the elimination method. 2x - 2y = 2. 5x + 2y = 12 (2, [?])​
nalin [4]

Answer:

(2,12)

Step-by-step explanation:

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3 years ago
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Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p repre
Anastasy [175]

Answer:

<h2>$26.25</h2>

<em><u>Solving steps:</u></em>

<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>

<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>

<em>Solution:</em><em> </em>Let the equation be

<h3><em>=> P = T </em><em>+</em><em>F</em></h3>

<u>p represent amount of money</u>

<u>p represent amount of moneyt represent total</u>

<u>p represent amount of moneyt represent totalf represent money found</u>

<h3><em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>

<u>insert the values</u>

<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>

add<u> 19.75 from 6.50 </u>

<h3><em>=> P = </em><em> </em><em>26.25</em></h3>

<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>

8 0
2 years ago
Can someone help me with #s 16 18 19 20 I WILL GIVE BRAINLIEST
Masteriza [31]

Answers & Step-by-step explanation:

<h2>PEMDAS (Parenthesis, exponents, multiplication, division, addition, subtraction)</h2>

Now let's solve your problems!

<h2>___________________________________________________</h2><h2>16.</h2>

First, we see if there are any parentheses. Since there are no parentheses, we will evaluate the exponent 3² first.

After this, our problem now looks like this:

<h2>\frac{41 - 9}{6 * 3 -26}</h2>

Next, since multiplication (not subtraction) is next on the list, we will evaluate 6 × 3, which equals 18.

After that, we will subtract:

41 - 9 = 32

18 - 26 = -8

We now have 32/-8 or 4/-1 or simply -4.

<h2>The answer is: -4</h2><h2>___________________________________________________</h2><h2>17.</h2>

With this, one, note the parentheses. This means that we will do these operations first.

(21 - 4²) = 5

(3 + 1) = 4

The problem now looks like this:

\frac{5 * 4}{8^{2}-44}

Next, we do the exponents:

8² = 64

After that, we do the multiplication of 5 x 4, which equals 20.

We now have 20/64 - 44, which simplifies to 20/20 or 1/1 or 1.

<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2>18.</h2>

Again, we see parentheses, so that means we need to do these operations first.

(6² - 20) = 16

We now have:

48 ÷ 16 + 5

48/16 = 3 and 3 + 5 = 8

<h2>The answer is: 8</h2><h2>___________________________________________________</h2><h2>19.</h2>

Here, we see an exponent 3³, so we'll need to evaluate this first.

3³ = 27

We now have:

4 × 27 ÷ 18 + 14

4 × 27 = 108

108/18 = 6

And finally:

6 + 14 = 20

<h2>The answer is: 20</h2><h2>___________________________________________________</h2><h2>20.</h2>

Here we again see the parentheses, which means we need to evaluate the subtraction first.

3 - 8 = -5

We now have:

11 + 2 (-5)

2 × -5 = -10

11 + -10 (same as 11 - 10) = 1

<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2><em>I AM ALWAYS HAPPY TO HELP :)</em></h2>
7 0
3 years ago
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