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Afina-wow [57]
2 years ago
10

I need to find the distance between (3,4) , (7,2)

Mathematics
1 answer:
fiasKO [112]2 years ago
4 0

Answer:

2\sqrt{5}

Step-by-step explanation:

Use the distance formula.

Subtract the x-coordinates and square the difference.

3 - 7 = -4; (-4)^2 = 16

Subtract the y-coordinates and square the difference.

4 - 2 = 2; 2^2 = 4

Add the differences and take the square root of the sum.

16 + 4 = 20; sqrt(20) = sqrt(4 * 5) = 2sqrt(5)

distance = 2sqrt(5)

You can use the distance formula which does the same thing.

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

d = \sqrt{(7 - 3)^2 + (2 - 4)^2}

d = \sqrt{(4)^2 + (-2)^2}

d = \sqrt{16 + 4}

d = \sqrt{20}

d = \sqrt{4 \times 5}

d = \sqrt{4} \times \sqrt{5}

d = 2\sqrt{5}

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What is the value of n?
faltersainse [42]

Answer:

  69

Step-by-step explanation:

The sum of exterior angles is 360°, so ...

  n° +131° +160° = 360°

  n° = 360° -291° = 69°

  n = 69

7 0
3 years ago
In the diagram of circle R, m∠FGH is 50°. What is m? 130° 230° 260° 310°
omeli [17]

we know that

The measurement of the exterior angle is the semi-difference of the arcs which comprises

In this problem

∠FGH is the exterior angle

∠FGH=50\°

∠FGH=\frac{1}{2}(arc\ FEH-arc\ FH)

50\°=\frac{1}{2}(arc\ FEH-arc\ FH)

100\°=(arc\ FEH-arc\ FH)  -----> equation A

arc\ FEH+arc\ FH=360\°

arc\ FH=360\°-arc\ FEH --------> equation B

Substitute equation B in equation A

100\°=(arc\ FEH-[360\°-arc\ FEH])

100\°=2arc\ FEH-360\°

2arc\ FEH=360\°+100\°

arc\ FEH=230\°

therefore

<u>The answer is</u>

The measure of arc FEH is equal to 230\°

6 0
3 years ago
Read 2 more answers
If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure
const2013 [10]

Answer:

DG = 26

GE = 26

DF = 15

CH = 14

CE = 28

Step-by-step explanation:

The figure has been attached, to complement the question.

DE = 52

FC = 15

HE = 14

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

DF = FC

CH = HE

DG = GE

Solving (a): DG

If DG = GE, then

DE = DG + GE

DE = DG + DG

DE = 2DG

Make DG the subject

DG = \frac{1}{2}DE

Substitute 52 for DE

DG = \frac{1}{2} * 52

DG = 26

Solving (b): GE

If DG = GE, then

GE = DG

GE = 26

Solving (c): DF

DF = FC

So:

DF = 15

Solving (d): CH

CH = HE

CH = 14

Solving (e): CE

If CH = HE, then

CE = CH + HE

CE = 14 + 14

CE = 28

7 0
3 years ago
Gaveing out points for helpers!!​
Alekssandra [29.7K]
Because the two angles add up to equal 90, you would make an equation set to equal 90. On the other end you add the measures of your angles together because they are adding up to equal 90. This would look like 2x+5+35=90 and you solve from here. Add like terms making it 2x+40=90 then you subtract 40 from both sides making it 2x=50 and then divide by 2 on both sides which leaves you with x=25.
3 0
2 years ago
De que otra manera puedo escribir z diferente a 7
kirza4 [7]
Puede ser el 2 creo pero espera a q algien más responda
3 0
3 years ago
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