Answer:
A) 3.44 ft²
Step-by-step explanation:
before cutouts, the area was 4 x 4 = 16 ft²
the circles have a diameter of 2 ft each, and a radius of 1 ft
each circle has an area pf (3.14)(1²) = 3.14 ft²
3.14 x 4 = 12.56 ft²
16 - 12.56 = 3.44 ft² left
Answer:
723 students participated in the event
Explanations:
The total number of students in Hanley's school = 1000
0.723 of the students participated in an event
Number of students that participated in the event = 0.723 x 1000
Number of students that participated in the event = 723
Answer:
No
Step-by-step explanation:
This is because it is a forever ongoing number. Here is an examples 7, pie, 5, and 2
tell me if this helped pls mark brainliest
The given MGF is that for a random variable following a Poisson distribution with parameter

.
This means

, and

has PMF

So, the desired probability is

This is equivalent to
Given functions are


The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).





Taking 2 as common, we get

Hence The total number of ducks and swans in the lake after n months is