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kaheart [24]
3 years ago
7

the interest earned on an account varies directly with the balance in the account. if an account with a balance of $200 earns $1

2.5 in interest, find the amount of interest earned on an account with a balance of 500
Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{\underline{I}nterest varies with \underline{b}alance}}{I=kb}\qquad \qquad \textit{we know that } \begin{cases} b=200\\ I=12.5 \end{cases} \\\\\\ 12.5=k200 \implies \cfrac{12.5}{200}=k\implies \cfrac{~~\frac{125}{10}~~}{\frac{200}{1}}=k\implies \cfrac{125}{10}\cdot \cfrac{1}{200}=k \\\\\\ \cfrac{1}{16}=k \qquad \qquad \textit{therefore}\qquad \boxed{I=\cfrac{1}{16}b} \\\\\\ \textit{when b = 500, what is \underline{I}?}\qquad I=\cfrac{1}{16}(500)\implies I=\cfrac{125}{4}\implies I=31.25

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il63 [147K]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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In which

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Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

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So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

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Step-by-step explanation:

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