Take -5x + y =13 and rearrange for y:
y=13+5x
Substitute into other equation for y:
-3x+3(13+5x)=3
Multiply out brackets:
-3x+39+15x=3
Simplify:
12x+39=3
Rearrange for x:
12x=-36
x=-3
Substitute back into y=13+5x:
y=13+5(-3)
y=13-15
y=-2
2x+8y
2x+8times2
2x+16
18x
Your final answer is 18x!
Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you! mark me as brainliest pls
§ALEX§
350 - 213 - 155 + 78 = 60 students not in either
Answer:
27.7
Step-by-step explanation:
90 - 62.3 = 27.7
