The cosine equation of the attached graph is; y = 5 cos [( π/40)(x - (π/2))] + 3
<h3>How to plot a trigonometric graph?</h3>
The given parameters are:
Diameter = 10 m
Thus;
Radius; r = 5 m
Time; t = 80 s
Height above the ground, h = 2 m
The above means that:
Amplitude; A = 5 m
Period, T = 80 s
Minimum = 2 m
The cosine function is represented as:
y = a cos [k(x - d)] + c.
where;
A is amplitude
B is cycles from 0 to 2π
period = 2π/k
d is horizontal shift
c is vertical shift (displacement)
Thus;
2π/k = 80
k = 2π/80 = π/40
Where
c = Amplitude - Minimum
c = 5 - 2
c = 3
Shift to the left by π/2 gives;
d = π/2
Thus, the equation of the cosine graph is;
y = 5 cos [( π/40)(x - (π/2))] + 3
Read more about Trigonometric Graph at; brainly.com/question/28054826
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Given:
Sum of three consecutive integers is more than 62.
To find:
The inequality to represent the above situation then solve your inequality.
Solution:
Let the three consecutive integers are
respectively.
Sum of three consecutive integers is more than 62. So,
![x+(x+1)+(x+2)>62](https://tex.z-dn.net/?f=x%2B%28x%2B1%29%2B%28x%2B2%29%3E62)
![3x+3>62](https://tex.z-dn.net/?f=3x%2B3%3E62)
Subtract 3 from both sides.
![3x>62-3](https://tex.z-dn.net/?f=3x%3E62-3)
![3x>59](https://tex.z-dn.net/?f=3x%3E59)
Divide both sides by 3.
![x>\dfrac{59}{3}](https://tex.z-dn.net/?f=x%3E%5Cdfrac%7B59%7D%7B3%7D)
Therefore, the required inequality is
and solution is
.
rounding to nearest 10 to any number follow these rules
1. if number ends 0 , 1 , 2 ,3 4 , 5 take number down to nearset multiple of 10
2. if number ends with above 5 take the upper number multiple of 10
so here
413 + 35.6 + 998.5 + 376 + 85.3
= 410 + 40 + 1000+ 380 + 90
= 1920
Answer:
4x + 7 = 10 + x
Step-by-step explanation:
It says sum of 4*x + 7, is equal to 10 + x. The reason for is contex clues, such as sum, ten more, than the number, times, and. These help us understand the operations and order that are happening.
The answer is:
6.2, 4.6, and 1.3 because you are going from greatest to least greatest..
Hope this helps :)