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Sladkaya [172]
3 years ago
8

Can someone help me with 16 and 20? If you’re supposed to write a contrapositive and inverse, but the word not is already in the

statement, what do you do?

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
Since 2 'not's cancel out, 16's contrapositive is 'If the light will go on, then the fuse has not blown'. In addition, the inverse would be 'If the fuse has not blown, then the light will go on'. I challenge you to do 20 using this information!
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Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

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4 0
2 years ago
What is the completely factored form of d4 -8d2 + 16
irinina [24]
According to Vieta's Formulas, if x_1,x_2 are solutions of a given quadratic equation:

ax^2+bx+c=0

Then:

a(x-x_1)(x-x_2) is the completely factored form of ax^2+bx+c.

If choose x=d^2, then:

\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm  \sqrt{64-64} }{2}=4

So, according to Vieta's formula, we can get:

x^2-8x+16=(x-4)(x-4)= (x-4)^2

But x=d^2:

d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2
8 0
3 years ago
Two sections took the same vocabulary qui. Use the 5-number summary 20,30 35 45 80) to construct a boxplot for Section and use t
gulaghasi [49]

Answer:

C. There are the same number of scores in Section and Section

Step-by-step explanation:

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7 0
3 years ago
What does (-0.75) (5/7) equal ?
Ludmilka [50]

Answer:

-0.53571428571

Step-by-step explanation:

4 0
3 years ago
For f(x) = 2x+1 and g(x)=x*2-7 <br> find (f/g) (x).
Lostsunrise [7]
(f/g)(x) = f(x)/g(x)
So the answer is C
I hope it will help
7 0
3 years ago
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