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Firlakuza [10]
3 years ago
8

The answer to the problem

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0
Ok so the top problem would be 
240 + 0.08 x 240
bottom one would be
240 + 19.20
PLEASE MARK BRAINLIEST
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t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.
kondaur [170]

Answer:

a) t = 1, b)  t = -2, c) Concave upward: (-\infty, 1). No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}

By factorizing each component, the function is re-arranged as:

f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}

There is no avoidable discontinuities. The only point where tangent line is vertical is t = 1.

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is  horizontal is t = -2.

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}

f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]

f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}

f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}

The only critical point is:

-6\cdot (t+2) = 0

t = -2 (which coincides with the result of point b)

f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]

f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}}  \right]

The value associated with the critical point is:

f''(-2) = \frac{2}{9}

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is (-\infty, 1). There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0
4 years ago
State is a given functions are inverses. NO LINKS!! Part 2<br><br>​
nadya68 [22]

Step-by-step explanation:

5.

g(x)=-2x+1

let y=2x+1

Interchanging role of x & y

x=2y+1

y=½x-½

g-¹(x)=½(x-1)

not

equal to f(x)=-x+1

<u>Given function are not function of each other</u> .

6.

g(x)=-x

let

y=-x

Interchanging role of x & y

x=-y

y=-x

g-¹(x)=-x

not

equal to f(x)=3+⅓x

<u>Given function are not function of each other .</u>

8 0
3 years ago
Read 2 more answers
1.03 divided by -10.3
Ivanshal [37]
-0.1 is your answer 
              __ -0.1_____________
                 I
     -10.3    I  1.03
     ______I

     
4 0
3 years ago
How would you simplify 585/16?
Alenkasestr [34]
You cant.............
5 0
3 years ago
Read 2 more answers
Find the length of lines DE.
Deffense [45]

This is known as The Theorem of Pythagoras

Basically is A2+B2+C2

Plug in the numbers as

16^2+B^2=30^2

Subtract 16 from both sides

16-16=0

30-16=14

Your Choice is A. 14cm


5 0
3 years ago
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