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lions [1.4K]
3 years ago
12

If you have a 7,052 mg gold nugget about how many grams would that be?

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:7.052 Grams (g)



Step-by-step explanation:

The milligram (symbol "mg") is a unit of mass, equal to 1/000 of a gram, and 1/10000000 of a kilogram

kotegsom [21]3 years ago
6 0
Answer 7.052 grams
hope it helps
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Evaluate a + b for a = 2 and b = 3
Vikki [24]

Answer:

5

Step-by-step explanation:

2+3+5

5 0
3 years ago
Which graph represents the solution set of y = x2 + 4x + 3 and y = 2x + 6?
dybincka [34]
I hope this helps you x^2+4x+3=2x+6 x^2+2x-3 =0 x +3 x -1 (x+3)(x-1)=0 x+3=0 x= -3 x-1=0 x=1
3 0
3 years ago
Read 2 more answers
PLEASE HELP MEEE!!!!
Tresset [83]

Answer:

I would say Inductive reasoning.

Step-by-step explanation:

Inductive reasoning is defined as "A method of reasoning in which a body of observations is synthesized to come up with a general principle." and this is exactly what the doctor did to come up with his diagnosis.

Hope this helps you out a bit.

4 0
3 years ago
Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
Negative of (-5) does not exist is true or false
Alinara [238K]

Answer:

Negative of 5 exists

It continues in the left part of a number line...

Hence the answer is false it does exist

3 0
3 years ago
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