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3 years ago

Am I right?

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

I think this MIGHT be right I’m not sure but yeah

Sliva [168]3 years ago

5 0

No it is 96 because you have six boxed each box has four jars which is 24 jars in total and each jar had four eggs so you have to do 24x4 which is 96 so the answer is 96

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HALP ME WITH THIS MATH PLSS

pentagon [3]

The answer is 63/5ft long of the actual car. Hope this helps :)

8 0

3 years ago

Read 2 more answers

Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

<em>a. The system of equations that models the situation is....</em>

<em>b. The solution to the system: x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

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3 years ago

A school newspaper decides to survey all the students enrolled in a gym class to determine the percentage of these students who

pishuonlain [190]

Answer:

A sudents who take gym class

Step-by-step explanation:

the survey only asks for all the students enrolled in a gym class so they can compare with the data for all the students enrolled in the football team

3 0

3 years ago

Find the perimeter of this shape<br>

Margaret [11]

The answer is 257.08m. Explanation: you know that one side of the square in the middle is 50m. This is the same as the diameter of one of the half circles on each side. The perimeter of a circle is the formula C=2(pi)r, where r is the radius. Dividing 50 by two will get you the size of the radius, then just plug it into the equation to find the perimeter of both rounded sides (a full circle). The two circular sides equal 157.08m, so then you just need to add the flat sides, which are both 50m since they’re congruent. 157.08m + 50m + 50m = 257.08m, so the perimeter of the shape is 257.08m.

4 0

3 years ago

Find the distance between points P(2, 2) and Q(7, 4) to the nearest tenth.

kirill115 [55]

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points P(2, 2) ans Q(7, 4). Substitute:

$|PQ|=\sqrt{(7-2)^2+(4-2)^2}=\sqrt{5^2+2^2}=\sqrt{25+4}=\sqrt{29}\approx5.4$

<h3>Answer: PQ = 5.4</h3>

8 0

3 years ago