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Gre4nikov [31]
3 years ago
9

If ΔSTU≅ΔHIJ, then what corresponding parts are congruent?

Mathematics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer:

The answer are given below.

The corresponding congruent angles are as follows

∠ STU ≅ ∠ HIJ

∠ TUS ≅ ∠ IJH

∠ UST ≅ ∠ JHI

The corresponding congruent sides are as follows

ST ≅ HI

TU ≅ IJ

SU ≅ HJ

Step-by-step explanation:

If Δ STU ≅ Δ HIJ ....... Given

if two triangles are congruent then

  • corresponding sides are congruent
  • corresponding angles are congruent

The corresponding congruent angles are as follows

∠ STU ≅ ∠ HIJ

∠ TUS ≅ ∠ IJH

∠ UST ≅ ∠ JHI

The corresponding congruent sides are as follows

ST ≅ HI

TU ≅ IJ

SU ≅ HJ

Ann [662]3 years ago
5 0

Answer:

D. segment US and segment JH

Step-by-step explanation:

answer for flvs exam

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galina1969 [7]

Answer:

1. 1 1/2

2. 5 1/4

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
What is mAngleMHJ? HELP pLEASE<br><br> 35°<br> 50°<br> 72.5°<br> 92.5°
telo118 [61]

Answer:

50°

Step-by-step explanation:

1) Opposite angles are the same. Therefore,

2x-20=x+15

2x-x=15+20

x=35

2) Put x back in the equation for angle mhj

2(35)-20=50

6 0
3 years ago
How many grams of NH3 are required to produce 4.65 g of HF
nignag [31]

1.326 grams of NH3 are required to produce 4.65 g of HF.

Step-by-step explanation:

Balanced chemical reaction is written first to know the number of moles taking part in original reaction.

NH3 +3 F2 ⇒3 HF  +  NF3

Given:

mass of HF = 4.65

First the number of moles of HF in 4.65 grams is calculated by using the formula:

number of moles (n) = \frac{mass}{atomic mass of 1 mole}

atomic mass of HF = 20 grams/mole

putting the values in the above equation number of moles can be found.

n = \frac{4.65}{20}

  = 0.235 moles of HF are given.

From the equation it can be said that:

1 mole of NH3 reacts to form 3 moles of HF

so, x moles of NH3 would react to form 0.235 moles of HF

\frac{3}{1} = \frac{0.235}{x}

3x = 0.235

x = \frac{0.235}{3}

x = 0.078 moles of NH3 is required.

The moles are converted to mass by applying the formula:

mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)

        putting the values in the formula

mass = 17 X 0.078

mass = 1.326 grams

8 0
2 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

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3 years ago
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Answer:

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Step-by-step explanation:

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