Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer:B
Step-by-step explanation:
Salesman B has no cap and get commission for everything he sells so how much he could make is over A because he has a cap and C doesn’t get commission.
Answer:
2403.2
Step-by-step explanation:
We get the length of the hypotenuse, and the base angle. To find the length of the base, we use the cosine of 16° since it is equal to the adjacent side length/ hypotenuse side length or cos 16°= x/2500. The isolate x by multiplying both sides by 2500. The cos 16° is around 0.96126, multiplied by 2500 (cos 16°(2500)) = 2403.1
Answer:
80.56%
Step-by-step explanation:
divide 36 by 29 and you get 0.8055555555. Change that into a percent to get 80.56%
Answer:
Step-by-stnxnep explanation: