+∞
∫ x · e ^(-x² ) dx = / The substitution: u = - x², x d x = - du / 2
-∞
+∞
= - 1/2 · ∫ e ^(u) du = - 1/2 · e ^(-x²) /
- ∞
e^(-∞) = 1 / e^(∞)
= -1/2 · [ 1/ e^(∞) - 1/ e^(∞) ] = -1/2 · ( 0 - 0 ) = 0
Answer:
just type the values in your google
Step-by-step explanation:
Step-by-step explanation:
slope/gradient
1 - (-4) / 4 - 0 = 5/4
y-intercept is -4 (this is the dot on y)
so the line equation is
y = 5/4x - 4 answer d
