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3 years ago

-0.75-(-2/5)+0.4+(-3/4)

Mathematics

1 answer:

RSB [31]3 years ago

6 0

-0.75-(-2/5)+0.4+(-3/4) = -0.7 simplified, how I got this answer can be found below in 16 steps.

1 - First thing we want to do is remove the parentheses.

-0.75 - (-2/5) + 0.4 - 3/4

2 - Then we simplify, multiply -1 by -1.

-0.75 + 1 (2/5) + 0.4 - 3/4

3 - Then multiply 2/5 by 1.

-0.75 + 2/5 + 0.4 - 3/4

4 - Then we want to write - 0.75/1 as a fraction with a common denominator, we do this by multiplying by 5/5.

-0.75/1 * 5/5 + 2/5 + 0.4 - 3/4

5 - Then we write each expression with a common denominator of 5, we multiply each one by a factor of one.

-0.75 * 5/1*5 + 2/5 + 0.4 - 3/4

6 - Then we multiply 5 by 1.

-0.75 * 5 / 5 + 2/5 + 0.4 - 3/4

7 - Then we combine the numerators over the common denominator.

-0.75*5+2/5+0.4-3/4

8 - We multiply -0.75 by 5.

-3.75 + 2/5 + 0.4 - 3/4

9 - Then we add -3.75 and 2.

-1.75/5+0.4-3/4

10 - And then we divide -1.75 by 5.

-0.35 + 0.4 - 3/4

11 - Then add -0.35 and 0.4.

0.05 - 3/4

12 - We then write 0.05/1 as a fraction with a common denominator, we do this via multiplying it by 4/4.

0.05/1 * 4/4 - 3/4

13 - Then we write each expression with a common denominator of 4, through multiplying each by a factor of 1.

0.05 * 4/4 - 3/4

14 - We combine the numerators over the common denominator.

0.05 * 4 - 3 / 4

15 - We simplify.

-2.8 / 4

16 - Then we divide -2.8 / 4

The final answer is -0.7

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This is a system of equations.
First, you set everything in terms of y.
Take the first equation and move set everything equal to y
y=0+2x
Since it’s 0, you don’t need to put it, so
y=2x works.
Then, you plug y=2x into the bottom equation, for the y.
-7x +3(2x)=2. You do this because now you have the same variable for both and it can be solved easily.
Then you can simplify.
-7x+3x = 2
Then combine like terms.
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You can check by plugging in both values to any of the equations. We will use the top one here.
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The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.

Therefore, the right answer is b. f(x) = 1/2(x + 11)^2 - 5

SECOND.

Translating 8 units to the right:

$g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2$

Then translating 1 unit down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1$

As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.

Therefore, the right answer is a. g(x) = 1/3(x - 8)^2 - 1

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