How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup led? A. V=2/81pir^2h
B. V=16/81pir^2h
C. V=4/9pir^2h
D. V=16/9pir^2h
1 answer:
New volume is given by: New volume=(old volume)×(4×2/9×2/9) simplifying the above we get: New volume=(old volume)×16/81 Thus the new volume is 16/81 times the old volume old volume=πr²h Hence: Answer:16/81πr²h
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