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4 years ago

9

2.5 inches for every 10 feet of run what is the slope

1 answer:

Nikolay [14]4 years ago

7 0

Rise/run 2.5/10 would be the answer

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padilas [110]

Answer: B

Trust me I took the test right now

6 0

3 years ago

2x + 3y = 3 y = 8 – 3x

pentagon [3]

2x + 3y = 3 y = 8 – 3x
we have 2 equations

first equations: <span>2x + 3y = 3 y
</span>the second equation: 3y = 8 – 3x => <span>8-3x=3y
</span><span>------------------------------------------------------------
2x+3y=3y</span>2x=3y-3y
2x=0
x=0

8-3x=3y
8-0=3y
8=3y
y=8/3

S={x=0 ; y=8/3 }

8 0

4 years ago

to buy the green and blue bikes would cost 1500$. to buy the green and red bikes would cost 750$. to buy all three bikes would c

lianna [129]

1500+750+2000=4,250 the answer is 4,250

5 0

3 years ago

The price of these item before VAT are as follows. What are the sale price if the VAT is charged at 15%?

Dimas [21]

Answer:

i will go with C TO BE REAL

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

4 years ago