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3 years ago

I need help this is due soon. Answers maybe...

Mathematics

1 answer:

bija089 [108]3 years ago

3 0

Answer:

points you can use : (0,0), (1,4), (2,8)

Step-by-step explanation:

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URGENT PLS RESPOND!!!

Elan Coil [88]

Answer:

$\huge\boxed{d=\sqrt{17}}$

Step-by-step explanation:

Simply use the fact that the change in x squared + the change in y squared = the distance squared. (The Pythagorean Theorem)

1^2 + 4^2 = d^2

1 + 16 = d^2

17 = d^2

d = √17

Hope it helps :)

6 0

3 years ago

Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p

Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0

3 years ago

Imagine you are painting a series of towers built from cubes. You are going to paint only the exposed faces of the cubes. What i

8_murik_8 [283]

A. Because the paint depends of the cubes
(I’m pretty sure)

3 0

3 years ago

In a standard deck there are 52 cards. If Event A is "the card is black" and Event B is "the card is a king," demonstrate the eq

Usimov [2.4K]

Answer:

you hcctch GB you know hmmm j yctcesbi bickel

7 0

3 years ago

Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)

Sati [7]

Answer:

tan(Sin^-1 x/2)= $\frac{x/2}{\sqrt{1-x^{2}/4 } }$

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1, one side of length x/2 and opposite angle of θ.

tan(Sin^-1 x/2) = tanθ

tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

tanθ= $\frac{x/2}{\sqrt{1-x^{2}/4 } }$

now substituting the value sin^-1 x/2= θ in above equation

tan(sin^-1 x/2) = $\frac{x/2}{\sqrt{1-x^{2}/4 } }$

3 0

3 years ago