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Nataliya [291]
3 years ago
13

When a point lie on the x-axis what do you know about its y coordinate? When a point lies on the y-axis,what do you know about i

t x-coordinate?
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
When the point is on the x axis, then the y coordinate=0
when the pointis on the y axis then the x coordinate=0 as well
oee [108]3 years ago
6 0
The to points are 0 
i hope that while help 

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What is the length of this rectangle?
solong [7]

Answer:

long

Step-by-step explanation:

well, as you can clearly see this is certainly not a short rectangle. maybe a little stocky, but certainly not short. also, I'm not very good at math, so dont ask me.

6 0
3 years ago
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Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

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4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
What is 15% of 12 meters
melomori [17]
Think of the "of" as a multiplication sign:
(.15)(12)= 1.8 meters
There you go! hope this helps with this problem and future ones.
7 0
3 years ago
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Quadratics Help please?
irakobra [83]
(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
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5 0
3 years ago
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A water cooler can hold 50 pt of water.
Nookie1986 [14]

Water cooler holds = 50 pt of water

1 L≈1.06 qt (which is the value of US liquid quart)

1.06 qt = 2.12 pt (which is the value of US liquid pint)

So when we are calculating how many liters of water cooler holds, divide the 50pt with 2.12pt

50pt/2.12pt = 23.6 Liters

<span>So 23.6 is the correct answer.</span>

6 0
3 years ago
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