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elixir [45]
3 years ago
14

Patrick counts on to solve 9+?=16 Explain how he can do this. What is the missing addend? Enter your answers in the boxes. Patri

ck could begin at ? and then count on until he gets to ? Since he counted on ? numbers,the missing addend is ?​
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

7

Step-by-step explanation:

9+7=16

Hope this helps

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Explain how you can solve 8x8 if you know how to multiply with 4 but not how to multiply with 8
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You can add 8, eight times
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A parking garage charges $5.50 to park for 4 hours and $7.75 to park for 7 hours. If the cost is a linear function of the number
Veseljchak [2.6K]
Given:
hours     parking charge
4                 5.50
7                 7.75

7 - 4 = 3 hours
7.75 - 5.50 = 2.25

2.25 / 3 = 0.75

0.75 is the change in amount for every hour spent. It is the variable unit rate

4 hours is 5.50.

Cost of parking for 3 hours is: 5.50 - 0.75 = 4.75

0.75 x 4 hours = 3 
5.50 - 3 = 2.5 fixed charge.

total parking charge:  y = 2.50 + 0.75x
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3 years ago
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Rewrite the equation below so that it does not have fractions.<br> 4 - 2/3x = 5/6
Lostsunrise [7]

Answer:

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6 0
4 years ago
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

4 0
3 years ago
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