The dog eats 6 cupcakes in 22 days.
<em>(don't know why a dog would be eating cupcakes in the first place, but sometimes math questions don't make the most sense)</em>
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
.00331125
Step-by-step explanation:
Answer:
SOLVE FOR X
x=2
Step-by-step explanation:
Answer:
a = 11/12
Step-by-step explanation:
1/3 + a =5/4
Subtract 1/3 from each side
1/3-1/3 + a =5/4-1/3
a = 5/4 -1/3
Get a common denominator of 12
a = 15/12 - 4/12
a = 11/12