A fence is 8.5 feet tall. How many inches tall is it?

Mathematics

1 answer:

babunello [35]2 years ago

7 0

Answer:

The answer is 102, good luck<3

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In January, a dealership sold 164 vehicles. In February, the same dealership sold 23.8% fewer vehicles than they sold in January

sattari [20]

23.8% of 164 is 39.032 so minus that off of 164 and you would've sold 124.968 cars and im guessing you should round so the dealership would've sold 125 cars.

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2 years ago

What is 2x squared times by 4

mina [271]

Since you can only multiply the 2 and 4 together, you get 8x^2.

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3 years ago

X2 + 5x - 50 = 0<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20-%2050%20%3D%200" id="TexFormula1" ti

love history [14]

Answer:

x = -10

x = 5

Step-by-step explanation:

${x}^{2} + 5x - 50 = 0 \\ (x + 10)(x - 5) = 0 \\ \\ x = - 10 \\ x = 5$

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2 years ago

Simplify.<br> 7x +84/(x + 12)(x+10)

Tasya [4]

Answer:

{7x^2+168x+840}/{x+12}

Step-by-step explanation:

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2 years ago

Is sin theta=5/6, what are the values of cos theta and tan theta?

mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}$

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2 years ago