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irga5000 [103]
3 years ago
8

There are 6 red marbles, 4 blue marbles, and 15 green marbles in a jar. If you reach in and randomly draw one, what is the proba

bility that you will choose a red marble
Mathematics
1 answer:
Sedbober [7]3 years ago
7 0
6  out of 20 or is that not correct
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All of the following are equivalent, except.
yulyashka [42]

Answer: B.

Step-by-step explanation: This is because you can't possibly have an exponent, there are no two of the same value being multiplied together.

5 0
2 years ago
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
mestny [16]

For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23,  we can approximate p hat by a normal distribution.

Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77

therefore,

n*p= 36*0.23 =8.28>5

n*q = 36*0.77=27.22>5

and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.

The question is incomplete, a possible complete question is:

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)

n*p = ?

n*q = ?

Learn to know more about binomial experiments at

brainly.com/question/1580153

#SPJ4

3 0
2 years ago
Solve the equation.
Elanso [62]

Answer:

A, a= 87

Step-by-step explanation:

a+36=123

Step 1: Subtract 36 from both sides.

a+36−36=123−36

a=87

Hope this helps!

4 0
3 years ago
Read 2 more answers
A symmetrical binomial distribution with large sample size can be approximated by a __________
sweet [91]
Typical distribution?
7 0
3 years ago
At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special. There are 5 c
Tju [1.3M]

Answer: 35

Step-by-step explanation:

Given : At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special.

The number of choices for sandwiches = 5

The number of choices for salad = 4

The number of choices for soup = 3

Now, the number of  possible lunch special combinations can be ordered will be :-

5\times4+5\times3=20+15=35

Hence, the number of  possible lunch special combinations can be ordered will be 35.

3 0
4 years ago
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