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3 years ago

Solve for x. x +7 / -3=1

Mathematics

1 answer:

ch4aika [34]3 years ago

7 0

<h3>I'll teach you how to solve x +7 / -3=1</h3>

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x +7 / -3=1

Subtract 7/-3 from both sides:

x+7/-3-7/-3=1-7/-3

Simplify:

x=10/3

Your Answer Is x=10/3

plz mark me as brainliest if this helped :)

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The radius of a circle is 13miles. what is the area of a sector bounded by a 20 degree arc

Stolb23 [73]

Answer:

Area of the sector = 29.48 square miles.

Step-by-step explanation:

Given:

Radius of a circle = 13 miles

Angle bounded by the arc = 20 deg

To find

Area of the sector bounded by 20 degrees.

Note: Area of a sector = $\frac{(\theta)}{360}\times \pi\times r^2$

Plugging the values in the equation.

⇒ $\frac{(\theta)}{360}\times \pi\times r^2$

⇒ $(\frac{20}{360})\times 3.14\times 13^2$

⇒ $29.48$ square-miles

So the area of the sector bounded by 20 degree arc is 29.48 square miles.

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3 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

The width to length ratio is ...

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3 years ago

Can you please help me<br> sorry this is hard for me but i’ll give u brainliest and 70 points

devlian [24]

Answer:

-9 + 5 = -4

Step-by-step explanation:

I think that's what your asking.....

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2 years ago

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