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Vika [28.1K]
3 years ago
5

Consider the set of A={0,3,5,8}​

Mathematics
1 answer:
Advocard [28]3 years ago
8 0
I dont really know, can you explain it better
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If you have 1 Pokeball and 2 pokemon heal balls and 3 pokemon Ultra balls. How many balls are there?
rusak2 [61]

Answer:

6

is the correct answer

<h2><em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
5 0
3 years ago
Given: 5x + 3 &gt; 4x + 7. Choose the graph of the solution set.
riadik2000 [5.3K]
Let's solve your inequality step-by-step.

<span><span><span>5x</span>+3</span>><span><span>4x</span>+7

</span></span>Step 1: Subtract 4x from both sides.

<span><span><span><span>5x</span>+3</span>−<span>4x</span></span>><span><span><span>4x</span>+7</span>−<span>4x

</span></span></span><span><span>x+3</span>>7

</span>Step 2: Subtract 3 from both sides.

<span><span><span>x+3</span>−3</span>><span>7−3

</span></span><span>x>4

</span>Answer:

<span>x><span>4</span></span>
4 0
3 years ago
Read 2 more answers
[2.5+ 0.187]x10 please help me
MAVERICK [17]
The answer will turn out to be 26.87
6 0
3 years ago
F (5^4)m = 512, what is the value of m? 2 3 5 8
MatroZZZ [7]

Answer:

questions is wrong??

Step-by-step explanation:

5^4 is 625

4 0
4 years ago
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}

Mean is represented by the following expression:

\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}\text{Mean}=\frac{84}{10}=8.4

Population variance formula looks like this:

\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}

Then, substituting:

\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}

For the standard deviation:

\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}

5 0
2 years ago
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