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scoundrel [369]
3 years ago
11

Easy 6th grader problem but I don't know it? PLEASE HELP 20 points

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

no it's easy u do it your self if u say it's easy

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A student claims that the rectangular point below can be represented by the
Sladkaya [172]

Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number.  I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )

P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)

sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)

Answer: TRUE

3 0
3 years ago
Grace is practicing free throws. The probability that she will shoot the ball into the basket is 5/9 . What is the probability t
Naddika [18.5K]

Answer:

There is a 25/81 probability that Grace will make both of her next two shots.

Step-by-step explanation:

The probability of her making the first shot is 5/9.

The probability of her also making the shot after that is still 5/9, that does not change.

To find the probability of both of those events, multiply the fractions.

5/9 * 5/9

25/81.

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Can someone help me with 1&amp; 2 will mark brainiest
melamori03 [73]
Sin 45° = opposite side / hypotenuse

1/2 = 8/h
h = 16

2)6/12 = 1/2
1/2 = sin 45°

6√3/12 = √3/2
√3/2 = cos 30°

Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°

Angles = 30° , 45° , 105°


7 0
3 years ago
Findes the slope from two points<br> point 1=(4,5)<br> point 2=(6,9)
hoa [83]

Answer:

2

Step-by-step explanation:

The formula for findining slope it y2-y1/x2-x1

so 9-5=4/ 6-4=2

4/2 is 2

the slope is 2

6 0
3 years ago
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