Step-by-step explanation:
Given that the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters.
A component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02
=P(|z|<1) (since 1 std dev on either side of the mean)
=2(0.3418)
=0.6826
=68.26%
The probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is
=P(1<z<2) (since between 1 and 2 std dev from the mean)
=0.475-0.3418
=0.3332
=33.32%
Answer:
12 11/35
Step-by-step explanation:
Given Data
First term= 15 3/5
To simple fracrion= 78/5
Second term= 3 2/7
To simple fracrion= 23/7
Hence the operation goes thus
= 78/5- 23/7
LCM = 35
=546-115/35
=431/35
=12 11/35
Y+8 = -3(x-7)
Distribute the -3
y +8 = -3x +21
Subtract 8 from both sides
Y = -3x +21 -8
Y= -3x+13
Answer:
B
Step-by-step explanation:
These lines are parallel so they have no solutions
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