x/2 + 4 < 7
multiply both sides by 2
x/2 * 2 + 4 * 2 < 7 * 2
which equals
x + 8 < 14
subtract 8 from both sides
x + 8 - 8 < 14 - 8
x < 6
Answer:
(4,6)
is the missing pair.
Step-by-step explanation:
Answer: Lets divide by 8. My god, those coefficients are large.
x^3 - 8x^2 + 20x - 16 = 0
Possible integral roots are: +1, -1, +2, -2, +4, -4, +8, -8
If x = 2, f(x) = 8 - 32 + 40 - 16 = 0
Hence, x-2 is a factor.
Use synthetic division to get: x^2 - 6x + 8 = (x-4)(x-2).
Therefore, there are two integral roots: +2 and +4.
Step-by-step explanation:
Answer:
f+g(2)=10
f-g(4)=-4
F/G(2)= 7/3
(f)(g)(1)=0
Step-by-step explanation:
1. (f+g)=2x+3+x^2-1 2(2)+2=10
2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4
3. f/g= 2x+3/x^2-1 4+3/3= 7/3
4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0
There is a difference of +3 between each number, so your following number would be 21+3 = 24
hope that helps :)
