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Paha777 [63]
3 years ago
15

If there are 26 successes in a sample with a size of 40what is the sample

Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0
El gobierno de la comunidad autónoma del gobierno ha decidido en un plazo
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Could 4.1 cm, 8.4 cm and 1.3 cm be the side lengths of a triangle? A Yes B No
oee [108]
No, the three given side lengths could not make a triangle.

8.4 cm is greater than 4.1 cm and 1.3 cm combined, so no matter what angle is between the two shorter sides, it is impossible to fit the 8.4 cm side.
4 0
4 years ago
Given that it was less then 80degrees on a given day, what is the probability that it also rained that day?
gladu [14]

The probability that it also rained that day would be 0.30

5 0
3 years ago
Please help me bro please
GaryK [48]

Answer:

  • n = 11°

⠀

Step-by-step explanation:

  • When two straight lines intersect each other, then the pairs of angles so formed without any common arm are called vertically opposite angles.

  • Vertically opposite angles are equal to each other.

⠀

So,

{\longrightarrow \it\qquad { \ { (6n   - 4) {}^{ \circ}   =  {(5n + 7)}^{ \circ} }}}

⠀

Removing the brackets,

{\longrightarrow \it\qquad { \ { 6n   - 4{}^{ \circ}   =  {5n + 7 \: }^{ \circ} }}}

{\longrightarrow \it\qquad { \ { 6n   - 5n   =  {  7 \: }^{ \circ} +4{}^{ \circ} }}}

{\longrightarrow \it\qquad { \pmb{ n   =  {  11 \: }^{ \circ}  }}}

⠀

Therefore,

  • The value of n is 11°
6 0
3 years ago
Read 2 more answers
Please help will give Brain
Lunna [17]
I think it’s the first option I’m sorry if that’s wrong
7 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
Read 2 more answers
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