All categories

3 years ago

If there are 26 successes in a sample with a size of 40what is the sample

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

El gobierno de la comunidad autónoma del gobierno ha decidido en un plazo

You might be interested in

Casey has 48 peppers and 16 yellow peppers . If he wants to put the peppers into baskets so that each basket has the same number

liraira [26]

Answer:

3 red peppers and 1 yellow pepper in each basket.

Step-by-step explanation:

We have been given that Casey has 48 peppers and 16 yellow peppers. He wants to put the peppers into baskets so that each basket has the same number of red and yellow peppers. We are asked to find the number of red and yellow papers in each basket.

To solve our given problem, we need to find greatest common factor of 48 and 16.

Prime factorization of 48 is $2\times 2\times 2\times 2\times 3$ .

Prime factorization of 16 is $2\times 2\times 2\times 2$ .

Greatest common factor of 48 and 16 would be $2\times 2\times 2\times 2=16$ .

Therefore, Casey can make 16 baskets with same number of red and yellow peppers.

Now we will divide 48 and 16 by 16 to find number of red peppers and yellow peppers in each basket respectively.

$\text{Red peppers in each baseket}=\frac{48}{16}=3$

$\text{Red peppers in each baseket}=\frac{16}{16}=1$

Therefore, there will be 3 red peppers and 1 yellow pepper in each basket.

6 0

4 years ago

Can somebody please help this is due very soon

joja [24]

Your answer is

Slope = -1.000/2.000 = -0.500
x-intercept = 7/1 = 7.00000
y-intercept = 7/2 = 3.50000

Step-by-step explanation:

4 0

2 years ago

How many nanoseconds does it take for a computer to perform one calculation if it performs 6.7 × 10^{7} calculations per second?

crimeas [40]

Answer:

the comuter does 1 calculation in 1.5* $10^{-17}$ nanosec

Step-by-step explanation:

First step: we need to write all terms in nanosec, as we know:

1[nanosec]= $10^{-9}$ [sec]

The computer does 6.7* $10^{7}$ [ $\frac{calculation}{sec}$ ]

if we multiplicate for $\frac{sec}{nanosec*10^{*9}}$ , from the units convertion.

6.7* $10^{7}$ [ $\frac{calculation}{sec}$ * $\frac{sec}{nanosec*10^{*9}}$

6.7* $10^{16}$ [ $\frac{calculation}{nanosec}$ ]

Now doing a simple three rule we have this:

6.7 * $10^{16}$ calculation in ⇒ 1 nanosec

1 calculation in ⇒ $\frac{1 nanosec* 1calculation}{6.7*10^{16} calculation }$

So, we found: the comuter does 1 calculation in 1.5* $10^{-17}$ nanosec

8 0

3 years ago

Write anAlgebraic expression-

Scilla [17]

Answer:

headboard ud. He. I’d Vic if joe

Step-by-step explanation:

3 0

3 years ago

What is the perpendicular for x+4y= -2

Elis [28]

First, set the equation up as y=mx+b then the perpendicular will be the opposite slope of your original slope

7 0

4 years ago