3 years ago

Q:

1 answer:

3 0

$a_1=200;\ a_2=196;\ a_3=192\\\\r=a_2-a_1\to r=126-200=-4\\\\a_n=a_1+(n-1)r\\\\a_n=200+(n-1)\cdot(-4)=200-4n+4=204-4n\\\\a_{14}=204-4\cdot14=204-56=148\\\\Answer:A$

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