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Komok [63]
3 years ago
6

Please answer these questions I have an f if I don't get help I will die

Mathematics
1 answer:
Softa [21]3 years ago
4 0

Answer:

rip just search em up and its kinda blurry sorry

Step-by-step explanation:

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Ayita made 5 1/2 cups of trail mix. She want to divide the trail mix into 3/4 cup servings.How many servings will she have?
lara [203]

Answer:

7

Step-by-step explanation:


3 0
3 years ago
Factor the trinomial:<br> 2x^2+15x+25<br> PLEASE HELP MEH
Savatey [412]

Answer:

(2x + 5) ( x + 5)

Step-by-step explanation:

2x² + 15 + 25

2x² + 10x + 5x + 25

2x( x + 5) + 5( x + 5)

(2x + 5) (x + 5)

3 0
3 years ago
Read 2 more answers
Negative 33 divided 11 as a fraction
Elodia [21]
-33 / 11 = ?

-33/11 

Simplify 

-3/1 would be the answer
6 0
3 years ago
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A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Shalnov [3]

Answer:

its 29

Step-by-step explanation:

6 0
3 years ago
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