A.6x+34
B.8t+38
C.2y-14
D.11n+16
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Answer:
around 66.66
Step-by-step explanation:
hope this helps
Label each nut with a variable, c = cashews, p = peanuts.....
for a 10-pound mix, you will need c + p = 10
the price for 10-pounds would become 3.29 x 10 = 32.90
You will need an unknown amount of cashews at 5.60/lb and an unknown amount of peanuts at 2.30/lbs to get your full 10 pounds valued at 32.90
5.60c + 2.30p = 32.90
Now you 2 have a system of 2 equations and 2 unknowns
c + p = 105.6c + 2.3p = 32.9utilize substitution to solve:p = 10-c
5.6 c + 2.3 (10-c) = 32.9
solve for c then substitute back into c + p = 10 to solve for P
Hope this helps!
