X = 7/4
y = 3/2
z = -5/4
Step 1: Multiply first equation by
<span>−3</span> and add the result to the third equation. The result is:
<span><span> x</span><span><span>+ 2 y</span><span>+ 3 y</span><span>− 8 y</span></span><span><span>− z</span><span>− 2 z</span><span>+ 8 z</span></span><span><span> = 6</span><span> = 7</span><span> = −22</span></span></span>
Step 2: Multiply second equation by 4 and add the result to the third equation. The result is:
<span><span> x</span><span><span>+ 2 y</span><span>+ 3 y</span><span>+ 4 y</span></span><span><span>− z</span><span>− 2 z</span></span><span><span> = 6</span><span> = 7</span><span> = 6</span></span></span>
Step 3: solve for y.
<span><span><span>4 y</span>y</span><span><span>=6</span><span>=<span>32</span></span></span></span>
Step 4: solve for z.
<span><span><span>3z−2z</span><span>3⋅<span>32</span>−2z</span>z</span><span><span>=7</span><span>=7</span><span>=−<span>54</span></span></span></span>
Step 5: solve for x by substituting <span>y=<span>32</span></span> and <span>z=−<span>54</span></span> into the first equation.
Answer:
C. 6
Step-by-step explanation:
8^2+r^2=10^2
64+r^2=100
r^2=36
Therefore, r=6
You could buy 276 single markers, you can buy 28 packs of markers, or 3 boxes of marker because 1pack = 10 markers, 10 markers multiplied by 10 packs equals 100. So 1 box would have 100 markers in it and if you took 2 boxes you would be missing 76 markers, so you're better off getting 3 boxes and having 300 markers than being less by 76.
B the only solution is X=9/10 therefore making it only one solution
Given that the goat pasture is rectangular with the dimensions given by:
Length=(y-4) and Width=(4y^2-3y+5)
Thus the area of the pasture will be given:
Area=length*width
Area=(4y^2-3y+5)(y-4)
Area=y(4y^2-3y+5)-4(4y^2-3y+5)
Area=4y^3-19y^2+17y-20
